Fluids & Heat

Specific Heat Converter

Specific heat capacity: J/(kg·K), kJ/(kg·K), J/(g·°C), cal/(g·°C) and BTU/(lb·°F). Calorie and BTU are International Table values unless marked thermochemical.

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1 Joule per kilogram kelvin = 0.000238845897 BTU per pound °F

Formula: divide the specific heat value by 4,186.8

Decimals

1 J/(kg·K) in every specific heat unit

Tap a row to convert to that unit.

How to convert specific heat units

Specific heat capacity: J/(kg·K), kJ/(kg·K), J/(g·°C), cal/(g·°C) and BTU/(lb·°F). Calorie and BTU are International Table values unless marked thermochemical. Every conversion goes through one base unit, the joule per kilogram kelvin, using exact factors, so results don’t drift.

Joules per kilogram kelvin to bTU per pound °F (J/(kg·K) to BTU/(lb·°F))

To convert joules per kilogram kelvin to bTU per pound °F, divide by 4,186.8. 1 joule per kilogram kelvin = 0.0002388459 bTU per pound °F.

J/(kg·K)BTU/(lb·°F)
1 J/(kg·K)0.0002388459 BTU/(lb·°F)
2 J/(kg·K)0.0004776918 BTU/(lb·°F)
5 J/(kg·K)0.001194229 BTU/(lb·°F)
10 J/(kg·K)0.002388459 BTU/(lb·°F)
20 J/(kg·K)0.004776918 BTU/(lb·°F)
50 J/(kg·K)0.01194229 BTU/(lb·°F)
100 J/(kg·K)0.02388459 BTU/(lb·°F)

BTU per pound °F to joules per kilogram kelvin (BTU/(lb·°F) to J/(kg·K))

To convert bTU per pound °F to joules per kilogram kelvin, multiply by 4,186.8. 1 bTU per pound °F = 4,186.8 joules per kilogram kelvin.

BTU/(lb·°F)J/(kg·K)
1 BTU/(lb·°F)4,186.8 J/(kg·K)
2 BTU/(lb·°F)8,373.6 J/(kg·K)
5 BTU/(lb·°F)20,934 J/(kg·K)
10 BTU/(lb·°F)41,868 J/(kg·K)
20 BTU/(lb·°F)83,736 J/(kg·K)
50 BTU/(lb·°F)209,340 J/(kg·K)
100 BTU/(lb·°F)418,680 J/(kg·K)

Joules per gram °C to calories per gram °C (J/(g·°C) to cal/(g·°C))

To convert joules per gram °C to calories per gram °C, divide by 4.1868. 1 joule per gram °C = 0.2388459 calories per gram °C.

Calories per gram °C to joules per gram °C (cal/(g·°C) to J/(g·°C))

To convert calories per gram °C to joules per gram °C, multiply by 4.1868. 1 calorie per gram °C = 4.1868 joules per gram °C.